At GCSE you met ethanol as a fuel and drink, made by fermentation. A-Level keeps the –OH functional group but asks far more of it: two industrial routes and their trade-offs, a 1°/2°/3° classification that decides what each alcohol does, controlled oxidation to three different products, and dehydration back to an alkene. The theme for the whole page: one –OH, but the reaction you run — and the alcohol’s class — changes everything.
Classifying alcohols & their properties
Before any reaction, sort the alcohol. Look at the carbon carrying the –OH group and count how many other carbon atoms are attached to it:
A primary (1°) alcohol has the –OH carbon bonded to one other carbon (or none, in methanol). A secondary (2°) alcohol has it bonded to two. A tertiary (3°) alcohol has it bonded to three.
This one label decides how — and whether — the alcohol oxidises later, so get quick at spotting it.
propan-1-ol · primary (1°)
1 other carbon on the –OH carbon
propan-2-ol · secondary (2°)
2 other carbons on the –OH carbon
2-methylpropan-2-ol · tertiary (3°)
3 other carbons on the –OH carbon
Interactive — classify the alcohol
Alcohols also behave differently from hydrocarbons physically, because the polar O–H group lets them form hydrogen bonds. That raises their boiling points well above alkanes and alkenes of similar size, and makes short-chain alcohols soluble in water.
- Classify by the –OH carbon, not the longest chain or the whole molecule.
- Higher boiling point than a comparable alkene is due to hydrogen bonding being stronger than van der Waals forces — never say covalent bonds break when it boils.
- Tertiary alcohols are the odd one out for oxidation — but examiner reports warn against making “tertiary” the answer to every “no reaction” question. Check which reaction is being blocked.
Recap structural isomerism and hydrogen bonding — both come up in alcohol exam questions.
🧪 Exam-style questions
Which statement is not correct for both primary and secondary alcohols? Tick (✓) one box.
The boiling point of pentan-2-ol is 119 °C; the boiling point of pent-1-ene is 30 °C. Explain why pentan-2-ol has the higher boiling point.
Show answer
Pentan-2-ol has stronger intermolecular forces (than pent-1-ene). 1 mark
Pent-1-ene has van der Waals (London / induced-dipole) forces only. 1 mark
Pentan-2-ol also has hydrogen bonds between molecules, which are stronger and need more energy to overcome. 1 mark
Do not accept any reference to breaking covalent bonds on boiling.
Source: AQA A-Level Chemistry past papers.
Making ethanol: two routes
Ethanol is made industrially two completely different ways, and AQA loves to make you compare them. One grows it; one builds it from crude-oil feedstock.
Hydration of ethene
Ethene from cracking is reacted with steam over a phosphoric acid (H3PO4) catalyst at about 300 °C and high pressure. The mechanism is electrophilic addition of water across the C=C — the same three arrows as the concentrated-sulfuric-acid route on the alkenes page, except that water itself is the nucleophile attacking the carbocation, so a final H+ is lost from the –OH2+ intermediate. That is exactly the dehydration mechanism further down this page, run in reverse.
CH2=CH2(g) + H2O(g) ⇌ C2H5OH(g)
It is continuous, fast, gives pure ethanol and has 100% atom economy — but the feedstock is non-renewable (crude oil) and it needs a lot of energy.
Fermentation of glucose
Sugars from plants are fermented by the enzymes in yeast, at about 35 °C, in the absence of air (anaerobic).
C6H12O6(aq) → 2C2H5OH(aq) + 2CO2(g)
The conditions are worth justifying: ~35 °C because the enzymes work too slowly when cold and denature when hot; no air because oxygen lets bacteria oxidise the ethanol to ethanoic acid (vinegar). It uses a renewable feedstock and little energy, but it is slow, runs in batches, and gives a dilute, impure mixture that must be concentrated by fractional distillation.
| Hydration of ethene | Fermentation | |
|---|---|---|
| Feedstock | ethene (crude oil) — finite | sugars / starch — renewable |
| Conditions | ~300 °C, high pressure, H3PO4 | ~35 °C, yeast, anaerobic |
| Rate & process | fast, continuous | slow, batch |
| Product | pure ethanol | dilute — needs fractional distillation |
| Atom economy | 100% | lower (CO2 by-product) |
Bioethanol & carbon neutrality
A biofuel is a fuel made from recently living material (biomass). Ethanol from fermentation is a biofuel, and is often called carbon-neutral — meaning no net carbon dioxide is added to the atmosphere, because the CO2 released when it burns was taken in by the plant during photosynthesis.
Follow the carbon through three equations — in one, out in two:
6CO2 + 6H2O → C6H12O6 + 6O2
C6H12O6 → 2C2H5OH + 2CO2
2C2H5OH + 6O2 → 4CO2 + 6H2O
Six CO2 in; two out in fermentation plus four out in combustion — six out. On paper, neutral. In practice it is not truly carbon-neutral: the machinery, fertilisers, transport and the distillation itself are usually powered by fossil fuels, and land that could grow food is cleared to grow the fuel crop instead.
hydration of ethene — continuous
Fast, pure product, 100% atom economy — but the ethene comes from crude oil
fermentation of glucose — batch
Renewable feedstock — but slow, batch, and the ethanol needs distilling
🧪 Exam-style questions
Which statement is correct about the production and use of ethanol as a biofuel? Tick (✓) one box.
Ethanol produced by fermentation of glucose may be regarded as a carbon-neutral fuel. Justify this statement. Include the relevant chemical equations in your answer.
Show answer
Photosynthesis: 6CO2 + 6H2O → C6H12O6 + 6O2 1 mark
Fermentation: C6H12O6 → 2C2H5OH + 2CO2 1 mark
Combustion: 2C2H5OH + 6O2 → 4CO2 + 6H2O 1 mark
The equations show 6 CO2 taken in by photosynthesis and 6 CO2 given out (fermentation + combustion), so there is no net release of CO2. 1 mark
Multiples of the equations are allowed; the final mark depends on the equations showing 6 CO2 in and out.
Source: AQA A-Level Chemistry past papers.
Oxidation of alcohols & Required Practical 5
This is the section the 1°/2°/3° label was for. The oxidising agent is acidified potassium dichromate(VI) (K2Cr2O7 with dilute H2SO4). When it does its job it changes orange solution to green solution (the dichromate(VI) ion Cr2O72− is reduced to green Cr3+). In equations you may use [O] to represent oxygen from the oxidising agent.
Primary alcohols — and the distil-vs-reflux choice
A primary alcohol oxidises in two stages: first to an aldehyde, then to a carboxylic acid. You choose which you get by how you run it:
- Want the aldehyde? Distil it off as it forms, using a limited amount of oxidant — the aldehyde has the lowest boiling point (no hydrogen bonding), so it leaves before it can be oxidised further.
- Want the carboxylic acid? Reflux with excess oxidant — heating without losing anything keeps the product in the flask to be oxidised the whole way.
Secondary & tertiary alcohols
A secondary alcohol oxidises to a ketone, and stops there (there is no easy further oxidation).
A tertiary alcohol is not oxidised by acidified dichromate — there is no hydrogen on the carbon bearing the –OH to remove — so the mixture stays an orange solution.
Interactive — warm an alcohol with acidified dichromate
Class of alcohol
Method — how far do you let it go?
Telling an aldehyde from a ketone
Both come from oxidising alcohols, and both contain C=O — but only the aldehyde is easily oxidised further, and two gentle reagents exploit that:
| Reagent | Aldehyde | Ketone |
|---|---|---|
| Tollens’ reagent | silver mirror forms | no change |
| Fehling’s solution | blue solution → brick-red precipitate | stays blue solution |
tollens’ reagent · warm gently
The aldehyde reduces Ag+ to silver metal on the glass; a ketone cannot
fehling’s solution · warm gently
The aldehyde reduces blue Cu2+ to brick-red Cu2O; a ketone leaves it blue
The aldehyde reduces the reagent as it is itself oxidised to a carboxylic acid. A ketone cannot be oxidised this way, so nothing happens.
Oxidising a primary alcohol and distilling off the aldehyde as it forms is the classic RP5 set-up: heat the flask, and the low-boiling aldehyde vaporises and condenses into the collection flask before it can be oxidised to the acid. Know the apparatus (pear-shaped flask, still head, thermometer at the side-arm, condenser with water in at the bottom) and why anti-bumping granules are added — both set-ups are drawn, labelled and animated in the figure above. Practical skills are examined across all three papers — see the required practicals page.
🧪 Exam-style questions
Which compound reacts to form a ketone when warmed with acidified potassium dichromate(VI)? Tick (✓) one box.
Which compound is produced when 1-phenylethanol, C6H5CH(OH)CH3, reacts with acidified potassium dichromate(VI)? Tick (✓) one box.
The alcohol CH3CH2CH2OH can be oxidised. Which compound cannot be produced by oxidation of this alcohol? Tick (✓) one box.
Propan-1-ol is oxidised to propanoic acid. State a simple chemical test that distinguishes the propanoic acid from the propan-1-ol, and give one observation for the test with each substance.
Show answer
Add sodium carbonate (or sodium hydrogencarbonate) solution. 1 mark
Propanoic acid: effervescence / bubbles (of CO2). 1 mark
Propan-1-ol: no visible change / no reaction. 1 mark
Do not accept a pH-meter reading. An acidified-dichromate test (orange solution → green solution with the alcohol, no change with the acid) also scores.
Source: AQA A-Level Chemistry past papers.
Elimination: dehydrating alcohols to alkenes
Run the hydration reaction backwards and you dehydrate the alcohol: remove a molecule of water and form a C=C double bond. The reagent is a hot concentrated acid catalyst — concentrated H2SO4 or H3PO4, around 170 °C.
C2H5OH → CH2=CH2 + H2O
It is an acid-catalysed elimination, and the mechanism is three moves:
- Arrow 1 — protonate: a lone pair on the alcohol’s oxygen attacks an H+, turning –OH into –OH2+ (a good leaving group).
- Arrow 2 — lose water: the C–O bond breaks, water leaves, and a carbocation forms.
- Arrow 3 — lose H+: a C–H bond on the next carbon donates its pair to form the C=C, releasing H+ — so the acid is a catalyst.
Interactive — build the dehydration mechanism
When the alcohol is unsymmetrical, the H+ can be lost from carbons on either side of the carbocation, so you get a mixture of alkenes (including E/Z isomers). Pentan-2-ol, for example, gives pent-1-ene and pent-2-ene.
Why bother? These alkenes can be turned into addition polymers without using monomers made from crude oil — a renewable route into plastics.
Ethanolic KOH gives the other elimination route to an alkene — compare it on the halogenoalkanes page.
🧪 Exam-style questions
Which compound can be dehydrated to form an alkene? Tick (✓) one box.
Which alcohol, when dehydrated, forms a mixture of alkenes? Tick (✓) one box.
Pent-1-ene is formed by the elimination of water from pentan-2-ol. State the reagent and condition for this reaction, and outline the mechanism.
Show answer
Reagent: concentrated sulfuric acid (or concentrated phosphoric acid). 1 mark
Condition: hot / temperature in the range 150–200 °C. 1 mark
Curly arrow from a lone pair on the alcohol O to H+ (protonation). 1 mark
Arrow from the C–O bond to the O on the protonated intermediate (water leaves → carbocation). 1 mark
Arrow from a C–H bond on C1 to the C–C bond, forming the C=C of pent-1-ene. 1 mark
All arrows double-headed. Penalise any extra, contradictory arrows at each stage.
Source: AQA A-Level Chemistry past papers.
Same alcohol, different reactions
The exam trap on this topic is mixing up the reactions. Oxidation and dehydration start from the same alcohol but need different reagents and give different products — and “tertiary” is not the answer to every “why no reaction?”. Read the verb: oxidise, dehydrate, reflux, distil.
| Do this to the alcohol… | Reagent / conditions | …and you get |
|---|---|---|
| Oxidise (1°, distil) | acidified K2Cr2O7, distil off | aldehyde |
| Oxidise (1°, reflux) | acidified K2Cr2O7, excess, reflux | carboxylic acid |
| Oxidise (2°) | acidified K2Cr2O7, warm | ketone |
| Dehydrate | hot conc H2SO4 / H3PO4 | alkene (+ water) |
- Examiner reports flag students confusing dehydration with oxidation — different reagent, different product.
- They also flag “tertiary alcohol” given as the default answer to any “no reaction” question. A tertiary alcohol resists oxidation, but it dehydrates fine — check which reaction is blocked.
- For the aldehyde/carboxylic-acid choice, name the technique: distil for the aldehyde, reflux for the acid.
Interactive — build the mark-scheme answer
“Butan-2-ol is warmed with excess acidified potassium dichromate(VI). Identify the organic product, explain the colour change you would observe, and state how you could show that the product is a ketone rather than an aldehyde.” [5 marks] Select every statement that earns a mark — and nothing that doesn’t. Order doesn’t matter: AQA credits each point on its own.
🧪 Capstone questions
Which compound produces (CH3)2CHCOCH3 when oxidised? Tick (✓) one box.
A student warms 2.0 cm3 of propan-2-ol (density 0.786 g cm−3) with excess acidified potassium dichromate(VI) and collects 0.954 g of propanone (CH3COCH3). Calculate the percentage yield. Give your answer to the appropriate number of significant figures.
Show answer
Mass of propan-2-ol = 2.0 × 0.786 = 1.572 g. 1 mark
Amount of propan-2-ol = 1.572 ÷ 60.0 = 0.0262 mol. 1 mark
Maximum mass of propanone = 0.0262 × 58.0 = 1.52 g. 1 mark
% yield = (0.954 ÷ 1.52) × 100 = 63% (2 sig figs). 1 mark
2 sig figs only, set by the 2.0 cm3 measurement. Allow error-carried-forward at each step.
Source: AQA A-Level Chemistry past papers.
The aldehydes, ketones and carboxylic acids you just made are studied fully at A2 in Aldehydes & Ketones (3.3.8) and Carboxylic Acids (3.3.9). Next, learn the tests that identify them all in Organic Analysis (3.3.6).
- Classify by the –OH carbon: 1° (one C attached), 2° (two), 3° (three). Alcohols hydrogen-bond, so higher bp than comparable alkenes.
- Production — hydration: ethene + steam, H3PO4, ~300 °C; fast, continuous, 100% atom economy, but non-renewable. Fermentation: C6H12O6 → 2C2H5OH + 2CO2; yeast, ~35 °C, anaerobic; renewable but slow and impure (needs fractional distillation).
- Biofuel: a fuel from living matter; bioethanol is near carbon-neutral (CO2 out balances CO2 taken in by photosynthesis) but not truly, because farming, transport and distillation use energy.
- Oxidation (acidified K2Cr2O7, orange solution → green solution): 1° → aldehyde (distil off) → carboxylic acid (reflux); 2° → ketone; 3° → no reaction.
- Aldehyde vs ketone: Tollens’ gives a silver mirror with an aldehyde only; Fehling’s gives a brick-red precipitate with an aldehyde only.
- Dehydration (hot conc H2SO4/H3PO4): alcohol → alkene + H2O, by acid-catalysed elimination (protonate –OH, lose water → carbocation, lose H+ → C=C). Unsymmetrical alcohols give a mixture of alkenes.