Whiteboard Chemistry with Joe White

Polymers

Condensation polymers — polyesters and polyamides — how their repeating units and linkages form, the intermolecular forces that give them their strength, and how (unlike polyalkenes) they can be hydrolysed back to their monomers.

AQA 7404/7405 Paper 2 A-level only
Hero motif · to come A chain, split at the link
The big idea

You already met addition polymers from alkenes — one monomer, nothing lost. This topic adds condensation polymers, where two functional groups join and a small molecule (usually water) is lost at every link. Those links are ester or amide groups — which means, unlike an inert polyalkene, the chain can be hydrolysed straight back to its monomers.

Condensation polymers

A condensation polymer forms when each monomer has two reactive groups, so the chain can grow from both ends. Every new link expels a small molecule — water (or HCl if an acyl chloride is used). Two families matter:

The two condensation polymer families
PolymerMonomersLinkageExamples & uses
Polyesterdicarboxylic acid + diolester link  –COO–Terylene — clothing fibres, bottles
Polyamidedicarboxylic acid + diamine (or amino acids)amide link  –CONH–nylon 6,6 (fibres, ropes); Kevlar (body armour)
Drawing the repeating unit

Join one of each monomer, remove the small molecule at the new link, and put the repeat unit in brackets with a trailing bond at each end (these show the chain continues). You should be able to work in both directions: monomers → repeat unit, and a section of chain → the monomers that made it.

Figure F1 · illustration to come Monomers → repeat unit Ester link for polyesters, amide link for polyamides — water lost each time.
Every link forms with the loss of a small molecule — the mark of a condensation polymer.
🧪 Exam-style questions
Q1 [1 mark]

Which compound can form a polymer with the diacyl chloride ClOC(CH2)8COCl?

  1. NH2CH2CH2NH2
  2. (CH3CO)2O
  3. CH3CH2CONH2
  4. NH2CH2COOH
A polymer needs a monomer with two reactive groups to react with the two acyl chloride ends. The diamine NH2CH2CH2NH2 forms a polyamide. (NH2CH2COOH could self-polymerise, but does not form a polymer with the diacyl chloride here.)
Q2 [2 marks]

An equation shows nylon 4,6 forming from five molecules of butane-1,4-diamine and five molecules of hexanedioic acid, releasing y molecules of water and giving a chain of x repeating units. Deduce x and y.

Show answer

x = 5 1 mark

y = 9 1 mark

(Five diamine + five diacid give five repeat units; joining ten monomers into one chain makes nine links, each losing one water.)

Source: AQA A-Level Chemistry past papers.

Forces between chains

A polymer’s strength and melting point come from the intermolecular forces between its chains — and the linkage decides how strong those are:

  • Polyamides have N–H and C=O groups, so chains hydrogen-bond to each other (N–H⋯O=C). These are the strongest forces here, giving high melting points and tough fibres — this is why Kevlar and nylon are so strong.
  • Polyesters have polar C=O and C–O bonds, so chains attract by permanent dipole–dipole forces — weaker than hydrogen bonds.
  • Polyalkenes (poly(ethene), poly(propene)) are non-polar, with only weak van der Waals forces between chains.
Figure F2 · illustration to come Hydrogen bonding between nylon chains N–H on one chain to O=C on the next — drawn as linear dashed lines.
If asked to draw them, show N–H⋯O=C as straight dashed lines, with a lone pair on the oxygen.
🧪 Exam-style questions
Q3 [1 mark]

Which polymer has hydrogen bonding between its chains?

  1. Kevlar
  2. Polythene
  3. PVC
  4. Terylene
Kevlar is a polyamide: its N–H and C=O groups hydrogen-bond between chains. Terylene (a polyester) has dipole–dipole forces; polythene has only van der Waals forces, and PVC has permanent dipole–dipole forces (from its polar C–Cl bonds) — but none of these three can hydrogen-bond.

Source: AQA A-Level Chemistry past papers.

Breaking the links — hydrolysis

Here is the key skill. Because a condensation polymer is held together by ester or amide links, water can break each one — the same hydrolysis you met with simple esters and amides, now applied at every link along the chain. There is one reliable way to do it on paper:

The method — break the bond, add OH and H
  1. Find each ester link (–CO–O–) or amide link (–CO–NH–).
  2. Break the bond between the carbonyl carbon and the O (ester) or N (amide).
  3. Add –OH to the carbonyl-carbon side — this remakes the –COOH of the carboxylic acid.
  4. Add –H to the other side — this remakes the –OH of the alcohol (from a polyester) or the –NH2 of the amine (from a polyamide).

Do that at every link and you are back to the monomers: a polyester gives its dicarboxylic acid + diol; a polyamide gives its dicarboxylic acid + diamine.

Figure F3 · flagship diagram · illustration to come Break the link, add –OH and –H, recover the monomers Polyester → diacid + diol; polyamide → diacid + diamine.
The –OH always goes on the carbonyl carbon; the –H goes on the O or N.

Hydrolysis can be driven by hot aqueous acid or hot aqueous alkali (NaOH). Under acid, a polyamide gives the diammonium salt and the diacid; under alkali, it gives the diamine and the dicarboxylate salt — but the “break the bond, add OH and H” picture gets you the fragments every time.

Why polyalkenes cannot be hydrolysed

A poly(alkene) chain is nothing but non-polar C–C and C–H bonds. There is no Cδ+ for water to attack, so the chain cannot be hydrolysed — which is exactly why poly(ethene) and poly(propene) are inert and non-biodegradable, while polyesters and polyamides break down over time.

Disposal & biodegradability

Because they can be hydrolysed, polyesters and polyamides are biodegradable; polyalkenes are not. Disposal routes each trade off differently: recycling saves raw materials and energy but needs sorting and cleaning; incineration recovers energy but can release toxic gases and CO2; landfill is cheap but uses land and, for polyalkenes, lasts almost indefinitely.

🧪 Exam-style questions
Q4 [1 mark]

Which type of polymer is not hydrolysed by heating with concentrated aqueous sodium hydroxide?

  1. poly(alkene)
  2. poly(amide)
  3. poly(ester)
  4. protein
A poly(alkene) has only non-polar C–C bonds and cannot be hydrolysed. Polyamides, polyesters and proteins all contain hydrolysable ester/amide links.
Q5 [1 mark]

Which statement concerning nylon-6,6 is correct?

  1. Butanedioic acid is one of the reactants used to make nylon-6,6.
  2. Nylon-6,6 is an addition polymer.
  3. Nylon-6,6 can be hydrolysed by aqueous sodium hydroxide.
  4. All molecules of nylon-6,6 have the same relative molecular mass.
Nylon-6,6 is a polyamide, so its amide links are hydrolysed by hot NaOH. It is made from hexanedioic acid (not butanedioic acid), it is a condensation polymer, and its chains vary in length so molecules differ in Mr.
Q6 [2 marks]

Explain why polyesters are biodegradable but polyalkenes are not.

Show answer

Polyesters contain polar C=O / C–O bonds (the ester link), so they can be attacked by water / nucleophiles and hydrolysed. 1 mark

Polyalkenes have only non-polar C–C bonds, which cannot be hydrolysed / are not attacked. 1 mark

Source: AQA A-Level Chemistry past papers.

Monomers ↔ repeat unit

Most polymer marks come down to reading structures in both directions and hydrolysing cleanly. Given monomers, join one of each and remove the small molecule to get the repeat unit; given a chain, cut it at the links and add back the –OH and –H to recover the monomers. The same “break the bond, add OH and H” move does both the hydrolysis and the monomer-recovery.

The marks that get dropped
  • Repeat units without trailing bonds at each end — they must show the chain continues.
  • Forgetting the small molecule lost (water, or HCl with an acyl chloride) in a condensation equation.
  • Hydrolysing to the wrong fragments — the –OH goes on the carbonyl carbon (making –COOH), the –H on the O or N.
  • Drawing hydrogen bonds badly: they run N–H⋯O=C as straight dashed lines, with a lone pair on the oxygen.

Examiner reports note that hydrolysis products are often incomplete — students break the link but forget to add the –OH and –H, leaving fragments that are not the real monomers. Add both every time.

Interactive “break the link” hydrolysis explorer loads here. The four-step method above is the static fallback.

🎯 Build the mark scheme — hydrolysing a polyamide

A polyamide is hydrolysed. Describe how you work out the products, and explain why a poly(alkene) cannot be hydrolysed. Award yourself a mark for each:

  • Break the amide link (the C–N bond).
  • Add –OH to the carbonyl carbon (→ –COOH) and –H to the nitrogen (→ –NH2).
  • The products are the dicarboxylic acid + diamine.
  • A poly(alkene) has only non-polar C–C bonds, so it cannot be hydrolysed.
3.3.12 Polymers — Quick-reference summary
  • Addition polymers: from alkenes (C=C), one monomer, nothing lost. Condensation polymers: two functional groups react, a small molecule (H2O or HCl) lost at each link.
  • Polyester = diacid + diol (ester link –COO–, e.g. Terylene). Polyamide = diacid + diamine or amino acids (amide link –CONH–, e.g. nylon 6,6, Kevlar).
  • Forces between chains: polyamides hydrogen-bond (N–H⋯O=C) → strong, high melting; polyesters have dipole–dipole; polyalkenes only weak van der Waals.
  • Hydrolysis: break each ester/amide link, add –OH to the C=O side and –H to the other — polyester → diacid + diol; polyamide → diacid + diamine. Polyalkenes cannot be hydrolysed (non-polar C–C).
  • Disposal: polyesters/polyamides are biodegradable (hydrolysable); polyalkenes are inert. Options: recycle, incinerate (energy, but pollutants), landfill (space, non-degrading).

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Polymer questions reward two skills: reading a chain to recover its monomers, and hydrolysing a link cleanly — break the bond, add –OH to one side and –H to the other. Sessions drill repeat units, hydrogen bonding and hydrolysis on real AQA past questions.

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